SOLUTION: I would appreciate it if a tutor could verify my answer to the below question. Solve for x: sqrt(5-x) +3=sqrt(3x+4) My answer: sqrt(3x+4)^2=[(sqrt(5-x)+3]^2 3x+4=(

Question 6843: I would appreciate it if a tutor could verify my answer to the below question.

Solve for x: sqrt(5-x) +3=sqrt(3x+4)

My answer:

sqrt(3x+4)^2=[(sqrt(5-x)+3]^2
3x+4=(5-x)+(6)sqrt(5-x)+9
3x+4=14-x+(6)sqrt(5-x)
4x-10=(6)sqrt(5-x)
(4x-10)^2=[(6)sqrt(5-x)]^2
16x^2-80x+100=36(5-x)
16x^2-80x+100=180-36x
16x^2-44x-80=0
(16x+20)(x-4)
16x+20=0 or x-4=0
16x/16=20/16 or x=4
x=-5/4 or x=4
****x=-5/4 is an extraneous solution****

In advance, thank you for your assistance!
Answer by longjonsilver(2297) (Show Source): You can put this solution on YOUR website!
you are correct, but the -5/4 value is a valid answer..if you know Complex numbers. If not, then you can indeed ignore this answer.
Well done.
Jon.

RELATED QUESTIONS
I would appreciate it if a tutor could please verify my answer for the below problem: (answered by longjonsilver)

How do i go about factoring: sqrt(128) I looked online on how to solve radicals and i... (answered by oscargut)

I need someone to please review my assignment solutions...I would greatly appreciate... (answered by stanbon)

Hello, I just want to doublecheck my answers if someone can help me. Solve the... (answered by jim_thompson5910,Alan3354,edjones)

I just need to check to see if these are right since the ones I have had double checked... (answered by Cintchr,checkley75)

Three separate questions for the experts: Question 1: Solve for x: logx5 = 1/3 My (answered by rapaljer)

Hello, I would appreciate it if a tutor could please help me verify my work for the... (answered by kchande)

Tutor I was wondering if you could help me with these two problems? 1.) Sqrt of 50... (answered by stanbon)

I would appreciate it if someone could help me out with this problem: Solve the... (answered by Alan3354)