SOLUTION: Please help.I can't solve this problem.
A right triangle is a triangle with one angle measuring 90°. In a right triangle, the sides are related by Pythagorean Theorem,cˆ 2=aˆ2+b
Algebra.Com
Question 66895: Please help.I can't solve this problem.
A right triangle is a triangle with one angle measuring 90°. In a right triangle, the sides are related by Pythagorean Theorem,cˆ 2=aˆ2+bˆ2, where c is the hypotenuse (the side opposite the 90° angle). Find the hypotenuse when the other 2 sides’ measurements are 6 feet and 8 feet.
Answer:
Show work in this space .
Answer by venugopalramana(3286) (Show Source): You can put this solution on YOUR website!
Please help.I can't solve this problem.
A right triangle is a triangle with one angle measuring 90°. In a right triangle, the sides are related by Pythagorean Theorem,cˆ 2=aˆ2+bˆ2, where c is the hypotenuse (the side opposite the 90° angle). Find the hypotenuse when the other 2 sides’ measurements are 6 feet and 8 feet.
Answer:
Show work in this space .
C^2=6^2+8^2=36+64=100=10*10
C=10 FEET
RELATED QUESTIONS
A problem that is not in the book - can you help me solve? Thanks
A right triangle... (answered by checkley75)
Need Help with this problem.
4) A right triangle is a triangle with one angle... (answered by venugopalramana)
Could someone please help me with this.
A right triangle is a triangle with one angle... (answered by stanbon,jai_kos)
Please help.
4) A right triangle is a triangle with one angle measuring 90°. In a... (answered by stanbon)
I am having problems solving this problem:
A right triangle is a triangle with one angle (answered by stanbon)
I'm not good with word problems. This stuff is hard and I can't wrap my brain around it. (answered by Socom491)
) I keep getting stuck please help
A right triangle is a triangle with one angle... (answered by stanbon)
Really need help.
4) A right triangle is a triangle with one angle measuring 90°. In a (answered by checkley71)
A right triangle is a triangle with one angle measuring 90°. In a right triangle, the... (answered by rodriguezh2)