SOLUTION: Problem 24: 3 sqrt -8/27 I believe this is not a real number, is this correct? If it is I would say it is -2/3 From here I am lost, hope you can help me:-)

Question 65678This question is from textbook Beginning algebra
: Problem 24:
3 sqrt -8/27
I believe this is not a real number, is this correct? If it is I would say it is -2/3 From here I am lost, hope you can help me:-) This question is from textbook Beginning algebra

Found 2 solutions by stanbon, checkley71:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
3 sqrt -8/27
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You are right in saying "this is not a Real Number".
It is not part of the Real Number System.
It is a number in the Complex Number System.
In that system it equals:
3[(2/3)sqrt(-2/3)]
=2isqrt(2/3)
Note: "i" is the square root of negative one.
=(2/3)isqrt6
Cheers,
Stan H.
Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
3SQRT-8/27 IF THIS IS 3 TIMES THE SQRT -8/27
3SQRT-(2*2*2)/(3*3*3)
3*2/3SQRT-2/3
6/3SQRT-2/3
2SQRT-2/3
________________________________
IF THIS IS THE CUBERT-8/27 THEN
CUBERT(-2*-2*-2)/(3*3*3)
-2/3

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