SOLUTION: is this correct? 1.) 32 2/5 (32 1/5) ^2 =(5 SQUARE ROOT 32)2 =5(SQUAREROOT 2X2X2X2X2)2 =(5 SQUARE ROOT )2 =5 SQUARE ROOT 2 X 5 SQUARE ROOT 2 =25 (2 SQUARE
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-> SOLUTION: is this correct? 1.) 32 2/5 (32 1/5) ^2 =(5 SQUARE ROOT 32)2 =5(SQUAREROOT 2X2X2X2X2)2 =(5 SQUARE ROOT )2 =5 SQUARE ROOT 2 X 5 SQUARE ROOT 2 =25 (2 SQUARE
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Algebra: Radicals -- complicated equations involving roots
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Question 641770
:
is this correct?
1.) 32 2/5
(32 1/5) ^2
=(5 SQUARE ROOT 32)2
=5(SQUAREROOT 2X2X2X2X2)2
=(5 SQUARE ROOT )2
=5 SQUARE ROOT 2 X 5 SQUARE ROOT 2
=25 (2 SQUARE ROOT 2)
=50 SQUARE ROOT 2
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Alan3354(69443)
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is this correct?
1.) 32 2/5
(32 1/5) ^2
=(5 SQUARE ROOT 32)2
=5(SQUAREROOT 2X2X2X2X2)2
=(5 SQUARE ROOT )2
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It's correct to here, except it's 5th root, not 5 square root
===================
Then it's just 2^2
= 4
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=5 SQUARE ROOT 2 X 5 SQUARE ROOT 2
=25 (2 SQUARE ROOT 2)
=50 SQUARE ROOT 2
