SOLUTION: The length of a rectangle is 4 meters longer than the width. If the area is 29 square meters, find the rectangles dimensions. Round to the nearest tenth of a meter. I know you a

Question 628329: The length of a rectangle is 4 meters longer than the width. If the area is 29 square meters, find the rectangles dimensions. Round to the nearest tenth of a meter.
I know you are only going to send me the answer, but how you got the answer would help me to understand how to solve a problem like this if I see it again. Thanks.
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
The length of a rectangle is 4 meters longer than the width.
If the area is 29 square meters, find the rectangles dimensions.
Round to the nearest tenth of a meter.
:
Let W = the width
It says,"The length is 4 meters longer than the width", therefore
L = W+4
:
The area = 29 sq/meters, therefore;
L * W = 29
Replace L with (W+4)
(W+4)*W = 29
W^2 + 4W = 29
A quadratic equation
W^2 + 4W - 29 = 0
Use the quadratic formula to find W

In this problem: x=W, a=1, b=4, c=-29

Two solutions, we only want the positive solution

W =
W ~ 3.7 meters is the width
then
3.7 + 4 ~ 7.7 is the length
:
:
Check this by finding the area:
7.7 * 3.7 = 28.49, not 29 because rounded to nearest 10th
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