SOLUTION: find the real roots of 16x squared -1=0
Algebra.Com
Question 611822: find the real roots of 16x squared -1=0
Answer by jsmallt9(3758) (Show Source): You can put this solution on YOUR website!
Since the highest exponent of x is 2, there will be two roots (although the roots might be complex, not real).
To find the roots, we want one side of the equation to be zero (which we already have) and then factor the other side. (Since this is a quadratic equation we we have option of using the Quadratic Formula. It is harder to use but it has the advantage of being able to find complex roots. Since we are only interested in real roots, we'll stick to factoring.
The GCF is 1 so we won't bother factoring it out. The left side is a difference of squares, , so it will factor according to that pattern: .
(4x+1)(4x-1) = 0
From the Zero Product Property we know that one of these factors must be zero. So:
4x+1 = 0 or 4x-1 = 0
Solving each of these we get:
x = -1/4 or x = 1/4
These are the two real roots for your equation.
RELATED QUESTIONS
Find all roots of the polynomial x cube-x... (answered by stanbon)
How would you find the roots and vertex of... (answered by Gogonati)
find the roots of 2x squared... (answered by jim_thompson5910)
kx(squared)-6x+5=0. Find the values of k for which the roots are real... (answered by stanbon)
Find the real roots of each equation.
25x^2-49=0
And
16x^2+8=9
And... (answered by nerdybill)
Use the rational zero theorem and quotient polynomials to find all roots of the given... (answered by lwsshak3)
complete the square, and find the roots of the quadratic equation.
x^2 + 16x =... (answered by venugopalramana)
complete the square, and find the roots of the quadratic equation.
x^2 + 16x =... (answered by Prithwis)
complete the square, and find the roots of the quadratic equation.
x^2 + 16x = 0
(answered by venugopalramana,stanbon)