SOLUTION: \/x+4=3
This is what I did:
(\/x+4)^2=3^2
x+8=9
x=1
Is this correct or did I miss a step?
Thank you!
ac
Algebra.Com
Question 57858: \/x+4=3
This is what I did:
(\/x+4)^2=3^2
x+8=9
x=1
Is this correct or did I miss a step?
Thank you!
ac
Answer by funmath(2933) (Show Source): You can put this solution on YOUR website!
I'm having trouble interpretting your problems because I know where your radicals begin, but I don't know where they end. If I misinterpret, let me know and I'll change it.
Check your answers everytime that you do square root problems for extraneous soltuions:
Our solution is fine, x=5
Happy Calculating!!!
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