SOLUTION: Hello what is the vertex of this quadratic and can you show me the steps of how you got this:
f(x)= -3/10x^2+9/2x-7/6
thank you
Algebra.Com
Question 553590: Hello what is the vertex of this quadratic and can you show me the steps of how you got this:
f(x)= -3/10x^2+9/2x-7/6
thank you
Found 2 solutions by stanbon, josmiceli:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
what is the vertex of this quadratic and can you show me the steps of how you got this:
f(x)= (-3/10)x^2+(9/2)x-(7/6)
--------
vertex occurs at x = -b/(2a)
= (-9/2)/(2(-3/10))
= (-9/2)/(-3/5)
= (-45/-6)
----
= 15/2
----
= 7.5
=============
f(7.5) = (-3/10)(7.5)^2+(9/2)(7.5)-(7/6) = 15.71
------
Vertex: (7.5 , 15.71)
===========================
Cheers,
Stan H.
===========================
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
The x-coordinate of the vertex is at
where the equation
has the form |
--------
----------------
So far, the vertex is at ( 15/2,y )
Now find the y-coordinate
The vertex is at (15/2, -109/24)
Unless I made a mistake
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