SOLUTION: √(6x+1)= x-1 Solve. I got 6x+1=x^2-2x+1 Subtracted 6x and 1 and got 0=x^2-8x+0 x(x-8) x=0 x=8 What did I do wrong? Thanks

You can put this solution on YOUR website!
√(6x+1)= x-1 Solve.
I got 6x+1=x^2-2x+1
Subtracted 6x and 1 and got 0=x^2-8x+0
x(x-8)
x=0
x=8
Now you have to check these answers to see if one
or both are extraneous.
Checking x=0 in the original problem you get:
sqrt(1)=-1. So x=0 is extraneous.
Checking x=8 in the original problem you get:
sqrt(49)=8-1=7
That is a good result. x=8 is your solution.
You might ask why you got an extraneous answer.
It happened when you squared both sides of the
equation. When you did that you introduced a
root that was not part of the original equation.
Cheers,
Stan H.

You can put this solution on YOUR website!
You need to check your answers with square root values.
sqrt(6 * 0 + 1) = 0 - 1
sqrt(1) = -1 Wrong *even though sqrt(1) = +- 1
sqrt(6 * 8 + 1) = 8 - 1
sqrt(49) = 7 True