SOLUTION: Suppose you throw an egg vertically into the air from a height of 6 feet above the ground at an initial velocity of 46 feet per second. h=-16t^2+46t+6 Find when the egg hit t

Question 539258: Suppose you throw an egg vertically into the air from a height of 6 feet above the ground at an initial velocity of 46 feet per second.
h=-16t^2+46t+6 Find when the egg hit the ground.
time in seconds / height of egg
0 / ?
.5 / ?
1 / ?
1.5 / ?
2 / ?
2.5 / ?
3 / ?
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Suppose you throw an egg vertically into the air from a height of 6 feet above the ground at an initial velocity of 46 feet per second.
h=-16t^2+46t+6 Find when the egg hit the ground.
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It hits the ground when h = 0.
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h=-16t^2+46t+6 = 0

Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=2500 is greater than zero. That means that there are two solutions: .

Quadratic expression can be factored:

Again, the answer is: -0.125, 3. Here's your graph:

-------------
t = x
Ignore the negative solution.
t = 3 seconds
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