SOLUTION: solve (w+2)^3+88=0 where w is a real number. write your answer in simplified radical form.
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Question 530049: solve (w+2)^3+88=0 where w is a real number. write your answer in simplified radical form.
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
solve (w+2)^3+88=0 where w is a real number.
:
(w+2)^3 = -88
Find the cube root of both sides
w + 2 =
factor inside the radical to reveal a perfect cube, -8
w + 2 =
extract the cube root of -8
w + 2 =
subtract 2 from both sides
w = - 2
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