SOLUTION: Can someone show me how to do this problem? Simplify. m^2/8 / m^5/16

Question 52204This question is from textbook Beginning Algebra
: Can someone show me how to do this problem?
Simplify. m^2/8 / m^5/16 This question is from textbook Beginning Algebra

Answer by funmath(2933) (Show Source): You can put this solution on YOUR website!
When you divide, you subtract exponents: (a^m)/(a^n)=a^(m-n) Therefore:
(m^2/8)/(m^5/16)
m^(2/8-5/16) When you subtract fractions you need a common denominator. In this case the common denominator is 16.
m^(2*2/8*2-5/16)
m^(4/16-5/16)
m^(-1/16) Usually, the directions want no negative exponents,(The rule: a^-n=1/(a^n)):
1/(m^1/16)
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