SOLUTION: Here are two problems I have been asked to rationalize and I pray I have done them correctly. Thank you so much. Andrea
(A)
(14 - sqrt x) / (sqrt x)
(14 - sqrt x)(sqrt x)
1
Algebra.Com
Question 50108: Here are two problems I have been asked to rationalize and I pray I have done them correctly. Thank you so much. Andrea
(A)
(14 - sqrt x) / (sqrt x)
(14 - sqrt x)(sqrt x)
14 sqrt x - x
(B)
(sqrt x) / (14 - sqrt x)
(14 sqrt x + x) / (196 - x)
Found 2 solutions by stanbon, tutorcecilia:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
(A)
(14 - sqrt x) / (sqrt x)
Multiply numerator and denominator by sqrt x to get:
(14sqrtx-x)/x
---------------------
(B)
(sqrt x) / (14 - sqrt x)
Multiply numerator and denominator by (14+sqrtx) to get
(14 sqrt x + x) / (196 - x)
Cheers,
Stan H.
Answer by tutorcecilia(2152) (Show Source): You can put this solution on YOUR website!
(A)
(14 - sqrt x) / (sqrt x)
(14 - sqrt x)(sqrt x)/(sqrtx)(sqrtx)
(14)(sqrtx)-(sqrtx)(sqrtx)/x
(14)(sqrtx)-(x)/x
.
(B)
(sqrt x) / (14 - sqrt x)
(sqrt x) (14 + sqrt x)/ (14 + sqrt x)(14 - sqrt x)
(sqrt x)(14)+ sqrt x)(sqrt x)/(14)(14)-(14)(sqrt x)+(14)(sqrtx)-(sqrtx)(sqrtx)
(sqrt x)(14)+ (x)/ (196) - (x)
14(sqrt x)+ (x)/ (196 - x)[I agree]
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