SOLUTION: IMMEDIATE HELP PLEASE!!!!! SERIOUSLY!!! PLEASE HELP ME NOW BECAUSE TIME IS RUNNING OUT!!!!! When fighting a fire, the velocity v of water being pumped into the air is modeled by

Question 487008: IMMEDIATE HELP PLEASE!!!!! SERIOUSLY!!! PLEASE HELP ME NOW BECAUSE TIME IS RUNNING OUT!!!!!
When fighting a fire, the velocity v of water being pumped into the air is modeled by the FUNCTION V=squareroot 2hg, where h represents the maximum height of the water and g represents the acceleration due to gravity (32 ft/s^2)
1A -PLEASE SOLVE FOR H
1B- The Babylon Fire Department mus purchase a pump that will propel water 80ft into the air. Will a pump that is advertised to project water with velocity of 70ft per second meet the fire departments need? EXPLAIN.
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!

ft/sec
-----------------
(1a)
Square both sides

Divide both sides by

(1b)
given:

Multiply both sides by

is between and ft/sec
That is the velocity of water that is
needed to reach a height of ft
A pump that projects water with velocity
of 70 ft/sec will not reach a height of ft
---------------------------
The height that the water will reach is:

ft
This is ft short
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