SOLUTION: I am having problems with my order...please help me. SOLVE EACH OF THE EQUATIONS. BE SURE TO CHECK YOUR SOLUTIONS. 2y+7 (square root sigh) + 4 = y I am confused as to wh

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Question 48099: I am having problems with my order...please help me.
SOLVE EACH OF THE EQUATIONS. BE SURE TO CHECK YOUR SOLUTIONS.
2y+7 (square root sigh) + 4 = y
I am confused as to what to do with the Y.

Answer by tutorcecilia(2144) About Me  (Show Source):
You can put this solution on YOUR website!
2y+7 (square root sigh) + 4 = y
%28sqrt%282y%2B7%29%29+%2B+4+=+y%29%29
%28sqrt%282y%2B7%29%29+%2B+4+-+4=+y+-+4%29%29
%28sqrt%282y%2B7%29%29+=+y+-+4%29%29
%28sqrt%282y%2B7%29%5E2%29+=+%28y+-+4%29%5E2%29%29
(2y+7) = (y - 4)(y - 4)
2y + 7 = y^2 -8y + 16
2y-2y + 7 = y^2 - 10y + 16
7 = y^2 - 10y + 16
7 -7 = y^2 - 10y + 16 - 7
0 = y^2 - 10y + 9 [Factor]
0 = (y - 9)(y - 1) [Set each factor equal to zero and solve for x]
y - 9 = 0
y = 9
.
y - 1 = 0
y = 1
.
y = 9 or y = 1 [Final answer]
.
Check by plugging either answer back into the original equation.