Hi,

Find a quadratic equation for the solutions of 1/3 and 5

 (x-1/3)(x-5) = 0

F	First terms

O	Outside terms

I	Inside terms

L	Last terms

  x^2 - 1/3x - 5x + 5/3 = 0

  x^2 - (16/3)x + 5/3 = 0

 3x^2 -16x + 5 = 0

 y =  3x^2 -16x + 5 





 

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