SOLUTION: Solve these radical equations.
2x= sqrt(10x+6)
sqrt(x+5)= 2x
sqrt(2x-15)= x/4
sqrt(2x-1)= x+8/2
Algebra.Com
Question 459718: Solve these radical equations.
2x= sqrt(10x+6)
sqrt(x+5)= 2x
sqrt(2x-15)= x/4
sqrt(2x-1)= x+8/2
Answer by Gogonati(855) (Show Source): You can put this solution on YOUR website!
To solve the equation , we squared both sides of equation
, set the equation equal to zero , using the
quadratic formula we find the roots of the equation.
, and the roots are:
, and .
After checking the roots we reject the root x=-1/2 because it doesn't satisfy the original equation.
Answer: The solution is x=3.
In the same way you can solve the other equations.
RELATED QUESTIONS
Solve.
{{{sqrt(x-1)+sqrt(x-4)=sqrt(2x-1)}}} (answered by jim_thompson5910)
1.) The solution to sqrt 2x+3 - sqrt x-1=1 is x=3? true or false
2.) The solution to... (answered by ikleyn)
Solve {{{sqrt(2x+1)-sqrt(x)=1}}}
(answered by jim_thompson5910)
sqrt(2x - 5) = sqrt(x +... (answered by fractalier)
sqrt(2x-5) - sqrt(x-3) = 1 (answered by mukhopadhyay)
sqrt(2x-5)-sqrt(x-3)=1 (answered by fz_shurtugal)
{{{sqrt(2x+15)-x=6}}} (answered by vleith,solver91311)
{{{ sqrt ( 2x-1 )+ sqrt ( 2-x ) =2 }}} (answered by josgarithmetic)
{{{ sqrt ( 2x-1 )+ sqrt ( 2-x )... (answered by Fombitz)