SOLUTION: The length of a rectangle is 2 cm more than 3 times its width. If the area of the rectangle is 83 cm^2, find the dimensions of the rectangle to the nearest thousandth. Ive trie

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Question 43205This question is from textbook Beginning Algebra
: The length of a rectangle is 2 cm more than 3 times its width. If the area of the rectangle is 83 cm^2, find the dimensions of the rectangle to the nearest thousandth.
Ive tried a million times to get this and I'm stumped.... This question is from textbook Beginning Algebra

Answer by Nate(3500) About Me  (Show Source):
You can put this solution on YOUR website!
width = w
length = 3w + 2
lw+=+area
%283w+%2B+2%29w+=+83
3w%5E2+%2B+2w+-+83+=+0
w+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
w+=+%28-2+%2B-+sqrt%28+2%5E2-4%2A3%2A%28-83%29+%29%29%2F%282%2A3%29+
w+=+%28-2+%2B-+sqrt%28+1000+%29%29%2F%286%29+
w+=+-1%2F3+%2B+sqrt%282%2A5%2A2%2A5%2A2%2A5%29%2F6
w+=+-1%2F3+%2B+10sqrt%2810%29%2F6 about 4.9371
PLUG:
length = 3w + 2 = length = 3(-1/3 + 10sqrt(10)/6) + 2 = 1 + 5sqrt(10)