SOLUTION: x^2+x+(√x^2+x)-2=0 I'm thinking this can be re-written as 2x^2+(√2x^2)-2=0 but I'm completely confused in all of this. At some point, don't I need to balance the rig

Question 422167: x^2+x+(√x^2+x)-2=0
I'm thinking this can be re-written as 2x^2+(√2x^2)-2=0 but I'm completely confused in all of this. At some point, don't I need to balance the right and the left side of the equation?
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
No, you can't do that, this is a toughie

:
= -
Square both sides
=
FOIL the left
=
combine on the left
= 0
= 0
What can you do with this? it won't factor, graph the original and the above equation, see what we have

find the x intercepts, -1.6, and + .62 (not exact) Correction!!
:
Check both values in the original equation, see if it works

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SOLUTION: x^2+x+(&#8730;x^2+x)-2=0 I'm thinking this can be re-written as 2x^2+(&#8730;2x^2)-2=0 but I'm completely confused in all of this. At some point, don't I need to balance the rig

SOLUTION: x^2+x+(√x^2+x)-2=0 I'm thinking this can be re-written as 2x^2+(√2x^2)-2=0 but I'm completely confused in all of this. At some point, don't I need to balance the rig