_________ x = √16x + 225 Square both sides _________ x² = (√16x + 225)² x² = 16x + 225 x² - 16x - 225 = 0 (x - 25)(x + 9) = 0 x - 25 = 0 x + 9 = 0 x = 25 x = -9 We must always check a radical equation Checking x = 25: _________ x = √16x + 225 ____________ 25 = √16(25) + 225 _________ 25 = √400 + 225 ___ 25 = √625 25 = 25 So x = 25 is a solution. Checking x = -9: _________ x = √16x + 225 ____________ -9 = √16(-9) + 225 __________ -9 = √-144 + 225 __ -9 = √81 -9 = 9 That is false, so x = -9 is not a solution. (But please don't get the idea that you discarded -9 because it is negative, as in many cases a negative solution checks. It just didn't happen to in this case). Edwin