SOLUTION: I am having trouble with a problem I cannot seem to figure out the next step on it. The problem goes as follows: Rationalize the denominator and simplify. The nth root is 7 r

Algebra ->  Algebra  -> Radicals -> SOLUTION: I am having trouble with a problem I cannot seem to figure out the next step on it. The problem goes as follows: Rationalize the denominator and simplify. The nth root is 7 r      Log On

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 Algebra: Radicals -- complicated equations involving roots Solvers Lessons Answers archive Quiz In Depth

 Click here to see ALL problems on Radicals Question 396715: I am having trouble with a problem I cannot seem to figure out the next step on it. The problem goes as follows: Rationalize the denominator and simplify. The nth root is 7 radical 8x^29/243x^8 I split the radical up betweent the top and bottom and then multiplied both sides by the bottom. I know those steps are correct, however, I do not know how to solve it from there. nth root 7 radical 8x^29/nth root 7 radical 243x^8 times the top and bottom by the nth root 7 radical 243x^8. Where do I go from here? Answer by Edwin McCravy(8912)   (Show Source): You can put this solution on YOUR website! ``` Don't split the radical up until you subtract the exponents of the x's Now split it up: Since the power of x is a multiple of 7 we can take it out of the radical on top, divide the exponent 21 by the index of the radical 7 and get x3 which we write in front of the top radical: Since 243 = 35, we replace 243 by that: We have 35 on the bottom, and we need 37 so that it will come out of the radical, so we multiply by Multiply under the radicals: Rewrite 8*9 as 72 and the denominator as just 3 Edwin```