SOLUTION: The expression \frac{\sqrt[3]{8 h^{-2} s^{-4}}} { \sqrt[3]{ h^{6} s^{4}}} equals kh^rs^t where r, the exponent of h, is: and t, the exponent of s, is: and k, the leading coef

Question 395752: The expression
\frac{\sqrt[3]{8 h^{-2} s^{-4}}} { \sqrt[3]{ h^{6} s^{4}}}
equals kh^rs^t
where r, the exponent of h, is:
and t, the exponent of s, is:
and k, the leading coefficient is: 2
I have worked it out and keep getting k as 2, which is correct, but I am also getting 2 as answers for r and t with the cubed root of hs left over. I can't seem to get it in the right format that they want.
Answer by richard1234(7193) (Show Source): You can put this solution on YOUR website!
We have

Cancelling out and simplifying the exponents we obtain

which implies k = 8, r= 4, t = -8.

Btw algebra.com doesn't parse LaTeX code...I really wish it did though, since it's a much better way to input math expressions.
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