Hi

Let x represent 

2x^2-9x+1=0   

|yes, quadratic equation may have up to two x-values that satisfy the equation









x = 4.386, x = 0.114 to the nearest thousandths



for ex:  x^2 +6x + 9 = 0 have only one unique solution x = -3

That is, the parabola only crosses x-axis at one point

        (x+3)(x+3) = 0



 

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