# SOLUTION: Compute the value of the discriminant and give the number of real solutions to the quadratic equation. -4x^2 + 4x - 1 = 0

Algebra ->  Algebra  -> Radicals -> SOLUTION: Compute the value of the discriminant and give the number of real solutions to the quadratic equation. -4x^2 + 4x - 1 = 0      Log On

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 Question 391873: Compute the value of the discriminant and give the number of real solutions to the quadratic equation. -4x^2 + 4x - 1 = 0Answer by stanbon(57219)   (Show Source): You can put this solution on YOUR website!Compute the value of the discriminant and give the number of real solutions to the quadratic equation. -4x^2 + 4x - 1 = 0 ---- Discriminant = 4^2-4*-4*-1 = 16 -16 = 0 ----- Two Real equal solutions. Cheers, Stan H.