SOLUTION: (3radical a - 2 radical b) (3radical + 2radical b)
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Algebra: Radicals -- complicated equations involving roots
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Question 38912
:
(3radical a - 2 radical b) (3radical + 2radical b)
Answer by
fractalier(2101)
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If you mean
(3rad(a) - 2rad(b)) * (3rad(a) + 2rad(b))
then you have a sum times a difference which equals the difference of their squares, so you get
[3rad(a)]^2 - [2rad(b)]^2 =
9a - 4b
