Hi

the vertex form of a parabola:  where(h,k) is the vertex

f(x) = -5x^2 - 60x - 181   Completing the square

f(x) = -5(x^2 + 12x) - 181

f(x) = -5[(x + 6)^2 -36] - 181

f(x) = -5(x + 6)^2 + 180 - 181

f(x) = -5(x + 6)^2 -1

Vertex is Pt (-6,-1)  Note: parabola opens downward as a < 0

 

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