SOLUTION: Need help! I have to turn in this assignment by tonight and I'm having problems with this.
1) Solve the following equations.
a) sqrt(x) - 2=1
Answer:
Show work in th
Algebra.Com
Question 37643: Need help! I have to turn in this assignment by tonight and I'm having problems with this.
1) Solve the following equations.
a) sqrt(x) - 2=1
Answer:
Show work in this space.
b)sqrt(x)^3 = 27
Answer:
Show work in this space.
c)3^sqrt(x)^2 = 9
Answer:
Show work in this space.
Found 2 solutions by longjonsilver, stanbon:
Answer by longjonsilver(2297) (Show Source): You can put this solution on YOUR website!
1.
now square both sides:
x = 9
2.
well you would square both sides then take the cube root of both sides. Alternatively since "raising to a power" and "rooting" are opposite processes, it doesn't actually matter the order we do this, so i shall find the cube root first:
--> x = 9
3.
or...
so by "symmetry" of this, we can say that
and also, is just x anyway, so
x = 2
jon.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
a) sqrt(x) - 2=1
sqrt(x)=3
Square both sides to get:
x=9
b)sqrt(x)^3 = 27
Square both sides to get:
x^3=27^2
Take the cube root of both sides to get:
x=(27^2)^(1/3)=[27^(1/3]^2
x=3^2=9
c)3^sqrt(x)^2 = 9
3^(sqrt(x)^2)= 3^2
sqrt(x)^2=2
Square both sides to get:
x^2=4
x=2
Cheers,
Stan H.
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