SOLUTION: x^2+6x-4=0 Please help me solve? x^2+6x-4=0 --- Use Quadratic Formula: x = [-6 +- sqrt(36-4*1*-4)]/2 ---- x = [-6 +- sqrt(52)]/2 --- x = [-6 +- 2sqrt(13)]/2 --- x =

SOLUTION: x^2+6x-4=0 Please help me solve? x^2+6x-4=0 --- Use Quadratic Formula: x = [-6 +- sqrt(36-41-4)]/2 ---- x = [-6 +- sqrt(52)]/2 --- x = [-6 +- 2sqrt(13)]/2 --- x =

Question 376277: x^2+6x-4=0
Please help me solve?
x^2+6x-4=0
---
Use Quadratic Formula:
x = [-6 +- sqrt(36-4*1*-4)]/2
----
x = [-6 +- sqrt(52)]/2
---
x = [-6 +- 2sqrt(13)]/2
---
x = [-3 +- sqrt(13)]
Found 2 solutions by stanbon, juicebae:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
x^2+6x-4=0
---
Use Quadratic Formula:
x = [-6 +- sqrt(36-4*1*-4)]/2
----
x = [-6 +- sqrt(52)]/2
---
x = [-6 +- 2sqrt(13)]/2
---
x = [-3 +- sqrt(13)]
============================
Cheers,
Stan H.
Answer by juicebae(1) (Show Source): You can put this solution on YOUR website!
x^2+6x-4=0
---
Use Quadratic Formula:
x = [-6 +- sqrt(36-4*1*-4)]/2
----
x = [-6 +- sqrt(52)]/2
---
x = [-6 +- 2sqrt(13)]/2
---
x = [-3 +- sqrt(13)]
RELATED QUESTIONS
Could you please help me with the following? Solve for x in {{{1-x-(2/(6x+1))=0}}}. My (answered by god2012,MathTherapy)
Hi, I do not understand how to reduce or when to reduce the fraction within the quadratic (answered by edjones,ewatrrr)
{{{2x^2-(4�sqrt (13)) x+2sqrt (13)... (answered by josgarithmetic)
Solve for x: sqrt x-6 + sqrt x+6 = 6 a. 3 b. 16 c. 10 d. Cannot be solved (answered by oscargut,stanbon)
sqrt(x+6) + sqrt(2-x) =... (answered by CubeyThePenguin)
Please help. use quadratic formula... (answered by jim_thompson5910)
Solve. x^2 + 6x -4 = 0 Here's what I think is the answer. Can someone tell me if... (answered by vleith,jim_thompson5910)
Was wondering if someone could help me figure out if they were done correctly. I... (answered by jim_thompson5910)
(sqrt(x-2)) + 4 - (sqrt(x+2)) + (sqrt(3)) =... (answered by jsmallt9)