SOLUTION: solve (x+3)(x-16)(x+2)>0 The solution set is {x ⎹ }

Question 365114: solve (x+3)(x-16)(x+2)>0 The solution set is {x ⎹ }
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
Break up the number line into 4 regions using the critical points of the function.
Region 1:(,)
Region 2:(,)
Region 3:(,)
Region 4:(,)
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For each region, choose a point in the region (not an endpoint).
Test the inequality.
If the inequality is satisfied, the region is part of the solution region.
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Region 1:

False, Region 1 is not part of the solution region.
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Region 2:

True, Region 2 is part of the solution region.
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Region 3:

False, Region 3 is not part of the solution region.
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Region 4:

True, Region 4 is part of the solution region.
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Solution Region:(,) U (,)
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Graphical verification: Look for regions where the function is above the x-axis ()
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SOLUTION: solve (x+3)(x-16)(x+2)>0 The solution set is {x &#9145; }

SOLUTION: solve (x+3)(x-16)(x+2)>0 The solution set is {x ⎹ }