SOLUTION: 1.explain why 3[sqrt] x^6=x2 for any value of x, but x[sqrt^6]= x3 only when x ≥ 0.

Question 363976: 1.explain why 3[sqrt] x^6=x2 for any value of x, but x[sqrt^6]= x3 only when x ≥ 0.
Answer by robertb(5830) (Show Source): You can put this solution on YOUR website!
The cube root of is equal to for any value of x because the sign of x is retained by the presence of the power 2. But can take on only non-negative values (because it is a square root!). Technically speaking, = ||, and so there would be a problem if x<0. For example, if we allow x <0, then , but a square root is always non-negative!
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SOLUTION: 1.explain why 3[sqrt] x^6=x2 for any value of x, but x[sqrt^6]= x3 only when x &#8805; 0.

SOLUTION: 1.explain why 3[sqrt] x^6=x2 for any value of x, but x[sqrt^6]= x3 only when x ≥ 0.