SOLUTION: {{{ sqrt 4x+1=2x-1 }}} I got this far. {{{ (sqrt4x)^2=(2x)^2-2 }}}

Algebra ->  Algebra  -> Radicals -> SOLUTION: {{{ sqrt 4x+1=2x-1 }}} I got this far. {{{ (sqrt4x)^2=(2x)^2-2 }}}      Log On

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Question 36205: +sqrt+4x%2B1=2x-1+ I got this far. +%28sqrt4x%29%5E2=%282x%29%5E2-2+
Answer by stanbon(48535) About Me  (Show Source):
You can put this solution on YOUR website!
sqrt 4x+1=2x-1
Square both sides to get:
4x+1 = 4x^2-4x+1
4x^2-8x=0
4x(x-2)=0
4x=0 or x-2=0
x=0 or x=2
Check these answers in the original equation.
x=0 is extraneous.
x=2 is valid.
Cheers,
Stan H.