SOLUTION: Find the y - intercept and the vertex......y = x^2 - 3x -4....Thank you for your help much appreciated.

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Question 358508: Find the y - intercept and the vertex......y = x^2 - 3x -4....Thank you for your help much appreciated.
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!

Hi,
Note: The general vertex form of a parabola, (h,k) is the vertex
completing the square to put into the vertex form of a parabola
y = x^2 - 3x -4
y = x^2 - 3x + 9/4 - 9/4 -4
vertex form is:
y =1*(x - 3/2)^2 - 25/4
Vertex is (3/2, - 25/4) a>0 Therefore parabola opens upward and vertex is the Minimum
y intercept is Pt(0,-4)

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