Hi

y = 4x^2

Note: general vertex form of a parabola,    (h,k) is the vertex

y = 4x^2 tells us (0,0) is the vertex.  a >0 therefore parabola opens upward

and the vertex pt(0,0)is the Minimum 

 

RELATED QUESTIONS

Hello. I do not know if this fits into the right category but I tried my best. Ok so I... (answered by algebrapro18)

Hi, can someone help please?

Graph the quadratic 

y=1/4x^2-2 

thank you.  (answered by Fombitz)

Can anyone help me with this assignment. I have tried for two days to do this one and I... (answered by stanbon)

Good Day! Can you please help me with this question. It's about the graphs of cosine... (answered by Alan3354)

can someone help me with the following problem please?
 
it asks to Find the points of... (answered by atif.muhammad)

I am trying to finish up an assignment and am very confused with the next two problems.... (answered by Alan3354,robertb)

Referring to the figure, match the system of linear inequalities
    with its graph.
    (answered by ewatrrr)

Hi,

I need help with the following,I tried but I not sure of my graph and I can post... (answered by checkley77)

I am having trouble understanding what to do for my Algebra 2 homework.

The... (answered by josgarithmetic)