# SOLUTION: Why does {{{sqrt(3x)}}}{{{""=""}}}{{{-6}}} not have a real solution?

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 Algebra: Radicals -- complicated equations involving roots Solvers Lessons Answers archive Quiz In Depth

 Question 358464: Why does not have a real solution?Found 2 solutions by Edwin McCravy, Alan3354:Answer by Edwin McCravy(8908)   (Show Source): You can put this solution on YOUR website!```Because when written with a radical Ö a square root or a 4th root , or a 6th root , 8th root , or any root with an EVEN index can never represent a negative number (that's not true with odd index roots). Therefore your equation has a square root written with a radical on the left, which means that the left side is NOT negative. Yet it is equal to a negative number on the right, which means it can have no real solution. Edwin``` Answer by Alan3354(30993)   (Show Source): You can put this solution on YOUR website!Why does not have a real solution? ---------------- Square both sides 3x = 36 x = 12 ------ Check: = +6, -6