SOLUTION: I am really stumped on this one. okay its [12sqrt20]/4[sqrt3]
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Algebra: Radicals -- complicated equations involving roots
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Question 34849
:
I am really stumped on this one. okay its
[12sqrt20]/4[sqrt3]
Answer by
stanbon(48535)
(
Show Source
):
You can
put this solution on YOUR website!
[12sqrt20]/4[sqrt3]
=12sqrt(4*5)/4sqrt3
=24sqrt5/4sqrt3
=6sqrt5/sqrt3
Now, multiply numerator and denominator by sqrt3 to get:
=6sqrt15/3
=2sqrt15
Cheers,
Stan H.