SOLUTION: Solve
The square root of x+1, Under the square root of 3=the square root of 3x-5
Algebra.Com
Question 339892: Solve
The square root of x+1, Under the square root of 3=the square root of 3x-5
Answer by edjones(8007) (Show Source): You can put this solution on YOUR website!
sqrt(3)/sqrt(x+1)=sqrt(3x-5)
3/(x+1)=3x-5
3=3x^2-2x-5
3x^2-2x-8=0
3x^2-6x+4x-8=0
3x(x-2)+4(x-2)=0
3x+4=0, x-2=0
x=2
.
Ed
RELATED QUESTIONS
square root of x+7=square root of 2x-3 (+2) not under the square... (answered by lynnlo)
the square root of 3x+5- the square root of... (answered by checkley77)
Please help! (2 x the square root of 3x - the square root of 5)(2 x the square root of 3x (answered by rapaljer)
how do I solve the square root of x+2 -1 outside the root = square root of... (answered by bucky)
square root of 5x plus the square root of... (answered by oberobic)
Solve:
Square Root of (x+3) = 2x
only (x+3) is under the Square Root
Thank you (answered by MathTherapy)
how do i solve
the square root of 3x-3 minus the square root of x plus 5 =... (answered by lwsshak3)
the square root of (3x+10) = 1 + the square root of... (answered by Cintchr,ikdeep)
square root of 3x+1 minus the square root of... (answered by Fombitz)