SOLUTION: I need to find the steps to from
(7√(2*2*3))/6 to 7/3 √3
I have been working on it for two days now. I just don't get it.
Algebra.Com
Question 338166: I need to find the steps to from
(7√(2*2*3))/6 to 7/3 √3
I have been working on it for two days now. I just don't get it.
Found 2 solutions by solver91311, CharlesG2:
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Two days is a very long time to be working on one radical simplification problem. What have you tried? What is your approach to the problem?
John
My calculator said it, I believe it, that settles it
Answer by CharlesG2(834) (Show Source): You can put this solution on YOUR website!
I need to find the steps to from
(7√(2*2*3))/6 to 7/3 √3
I have been working on it for two days now. I just don't get it.
let's see if I can figure it out
sqrt = square root = √
(7 * sqrt(2 * 2 * 3))/6 to 7/3 * sqrt(3)
(if I mistyped or misinterpreted, I apologize)
numerator:
7 * sqrt(12) = 7 * sqrt(4 * 3) = 7 * sqrt(2 * 2 * 3) (factoring)
7 * sqrt(12) = 7 * 2 * sqrt(3)
(there were two 2's inside the square root, sqrt(4) = 2)
denominator:
6 = 2 * 3
the 2's in the numerator and denominator cancel out
left with:
7/3 * sqrt(3)
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