_ __ 7Ö3 - 5Ö75
_ __ 7Ö3 - 5Ö75 Break 75 into its prime factors: 75 = 3·25 = 3·5·5 = 3·5², so replace 75 by 3·5² _ ____ 7V3 - 5Ö3·5² Take individual square roots of 3 and of 5²: _ _ __ 7Ö3 - 5Ö3·Ö5² The square root of 5² is just 5 _ _ 7Ö3 - 5Ö3·(5) _ _ 7Ö3 - 25Ö3 _ Factor out Ö3 _ Ö3(7 - 25) Combine what's in the parentheses _ Ö3(-18) _ -18Ö3 Edwin AnlytcPhil@aol.com
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