SOLUTION: Solution A is 10% alcohol, solution B is 60% alcohol.How much of each is needed to make 50 liters of a solution that is 30% alcohol?
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Question 32895This question is from textbook Algebra 1
: Solution A is 10% alcohol, solution B is 60% alcohol.How much of each is needed to make 50 liters of a solution that is 30% alcohol?
This question is from textbook Algebra 1
Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
A+B=50 & .1A+.6B=50*.3 OR A=50-B SUBSTITUTING IN EQUATION #2 WE GET
.1(50-B)+.6B=15 OR 5-.1B+.6B=15 OR .5B=10 OR B=20 THEREFORE A=50-B OR A=30
PROOF .1*30+.6*20=50*.3 OR 3+12=15 OR 15=15
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