SOLUTION: Question involvin radicals: parentheses, 6*sq.root of 2 minus 2* sq. root of 6, parentheses, everything squared.
Algebra.Com
Question 32805: Question involvin radicals: parentheses, 6*sq.root of 2 minus 2* sq. root of 6, parentheses, everything squared.
Answer by mukhopadhyay(490) (Show Source): You can put this solution on YOUR website!
[6sqrt(2) - 2sqrt(6)]^2
= [6sqrt(2)]^2 - 2*6*sqrt(2)*2*sqrt(6) + [2sqrt(6)]^2
= 36*2 - 24 sqrt(12) + 4*6
= 72 - 48 sqrt(3) + 24
= 96 - 48 sqrt(3)
= 48[2 - sqrt(3)]
RELATED QUESTIONS
My question is: sq root of 3 divided by (sq root of 15 minus sq root of 6)
Thank... (answered by Fombitz)
2 times sq. root of x minus sq. root of... (answered by edjones)
3 SQ. ROOT OF 8 + 2 SQ. ROOT OF... (answered by kara!)
Please show how to work out:
6 the sq root of 20 plus 8 the sq root of 5 minus 5 the sq (answered by Alan3354)
(3to sq. root of 3 + sq. root of 15)... (answered by Alan3354)
sq. root of 3/5
sq. root of 3 13/3
sq. root of 3{2}+5{2}
sq. root of m^2/n^3... (answered by checkley75)
another problem:
sq root of x-2 divided by sq root of... (answered by funmath)
A rational number between -sq root of 2.01 and -sq root of... (answered by Alan3354)
Find the polar form of the following expression: 3 sq root 2 - 3 sq root 2i?
(answered by user_dude2008)