The square root radical  never indicates
a negative number.  Therefore the right side of the above equation
cannot be negative.  Therefore the left side, which begins with a
negative sign, could only have value 0.  However that would make
 be 0, which would give .  However, if we 
substitute  in the right side we get  which
is undefined with real numbers.

So, there is no solution unless the - sign in front of the left
side was typo.  If it was a typo, post again without the typo.

Edwin