SOLUTION: radical 250 x^5 y^3

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Question 314204: radical 250 x^5 y^3
Found 2 solutions by Fombitz, Edwin McCravy:
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
sqrt%28250x%5E5y%5E3%29=sqrt%2850%5E2x%5E4y%5E2%2Axy%29
sqrt%28250x%5E5y%5E3%29=sqrt%2850%5E2x%5E4y%5E2%29sqrt%28xy%29
sqrt%28250x%5E5y%5E3%29=50x%5E2y%2Asqrt%28xy%29
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EDIT: Oops, that tutor is CORRECT. It's 250 not 2500.
sqrt%28250x%5E5y%5E3%29=sqrt%285%5E2x%5E4y%5E2%29sqrt%2810xy%29
sqrt%28250x%5E5y%5E3%29=5x%5E2y%2Asqrt%2810xy%29

Answer by Edwin McCravy(20086) About Me  (Show Source):
You can put this solution on YOUR website!

The other tutor's solution is incorrect. He must have mistook
250 for 2500.

Later: He came back and fixed it!

sqrt%28250x%5E5y%5E3%29

250 is not a perfect square but it can be broken up into a perfect square
times a non-perfect square, for it can be broken up into 25*10, where 25 
is a perfect square and 10 is a non-perfect square. so write 250 as 25*10.

sqrt%28red%2825%29%2A10x%5E5y%5E3%29

x%5E5 is not a perfect square but it can be broken up into a perfect square
times a non-perfect square, for it can be broken up into x%5E4%2Ax, where x%5E4
is a perfect square and x is a non-perfect square. so write x%5E5 as x%5E4%2Ax.

sqrt%28red%2825%29%2A10red%28x%5E4%29%2Ax%2Ay%5E3%29

y%5E3 is not a perfect square but it can be broken up into a perfect square
times a non-perfect square, for it can be broken up into y%5E2%2Ay, where y%5E2
is a perfect square and y is a non-perfect square. so write y%5E3 as y%5E2%2Ay.

sqrt%28red%2825%29%2A10red%28x%5E4%29%2Ax%2Ared%28y%5E2%29%2Ay%29

Notice that I've colored all the perfect squares red. We can take their square
roots.

The square root of 25 is 5, so we can take out the 25 as a 5 in front of
the radical.

red%285%29sqrt%2810red%28x%5E4%29%2Ax%2Ared%28y%5E2%29%2Ay%29

The square root of x%5E4 is x%5E2, so we can take out the x%5E4 as
an x%5E2 in front of the radical.

red%285x%5E2%29sqrt%2810x%2Ared%28y%5E2%29%2Ay%29

Finally the square root of y%5E2 is y, so we can take out the y%5E2 as just 
y in front of the radical.

red%285x%5E2y%29sqrt%2810xy%29.

Edwin