SOLUTION: When I try to graph or solve for (x)^(1/3) or other odd roots, I get a complex number when x is negative. I know that (-2)^3 = -8, so why isn't (-8)^1/3 =-2? I am trying to learn

Question 30507: When I try to graph or solve for (x)^(1/3) or other odd roots, I get a complex number when x is negative. I know that (-2)^3 = -8, so why isn't (-8)^1/3 =-2? I am trying to learn how to do the basics on a TI-89 T.
Thanks, Bruce
Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
But it is!
and if you were to cube both sides:
=
On both the TI-86 and the TI-89 Titanium, I get:

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