SOLUTION: Describe how to translate the graph y=sqrt(x) to obtain the graph of y=sqrt(x+5)
Please help with this math problem. I will appreciate your kind response.
Algebra.Com
Question 303639: Describe how to translate the graph y=sqrt(x) to obtain the graph of y=sqrt(x+5)
Please help with this math problem. I will appreciate your kind response.
Found 2 solutions by stanbon, graphmatics:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
x=sqrt(3x+40)
---
Square both sides to get:
x^2 = 3x+40
Rearrange:
x^2 - 3x - 40 = 0
---
x^2-8x+5x-40 = 0
x(x-8)+5(x-8) = 0
(x-8)(x+5) = 0
--------------
x = 8 or x = -5
---
Checking:
8 = sqrt(24+40)
8 = sqrt(64)
true
---
-5 = sqrt(-15+40)
false
====================
Only solution: x = 8
=========================
Cheers,
Stan H.
Answer by graphmatics(170) (Show Source): You can put this solution on YOUR website!
Since they are both graphs of square root expression we should a a value to one expression to translate that expression to the other
sqrt(x)+z = sqrt(x+5)
z = sqrt(x+5)-sqrt(x)
So
to translate y = sqrt(x) simply add sqrt(x+5)-sqrt(x)
to get
y=sqrt(x+5)
RELATED QUESTIONS
Hi, I am having issues with the topic "combinations of transformation" a specific problem (answered by josgarithmetic)
hello i have a question with this problem, I am not sure how to read the graph with the... (answered by MathLover1)
Describe how to translate the graph of g(x)=ln x into the graph of... (answered by stanbon)
how to sketch the graph of
y=... (answered by macston)
how would you change the graph of y=sqrt(x) to get the graph of y=sqrt(x+5)? (hint: which (answered by richard1234)
Sketch the graph of y=sqrt(x) and y=sqrt(x-1) + 2 and describe how the graphs are... (answered by ewatrrr)
Describe the transformations that must be applied to the graph of y= x^2 to obtain the... (answered by Boreal,greenestamps)
I need to figure out how to describe the graph of the equation y= 4/x + 1. Please... (answered by KMST)
Can someone help me with this i've tried and i am not ending up with the right solutions.
(answered by tutorcecilia)