SOLUTION: (4x^-2)-x^-1-5 put in quadratuc form to find x.

Question 295412: (4x^-2)-x^-1-5 put in quadratuc form to find x.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
(4x^-2)-x^-1-5 put in quadratic form to find x.
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4(x^-1)^2 - (x^-1) - 5 = 0
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To solve for "x" use the quadratic formula:
x^-1 = [1 +- sqrt(1-4*4*-5)]/8
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x^-1 = [1 +- sqrt(81)]/8
x^-1 = [1 +- 9]/8
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x^-1 = 10/8 or x = -1
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So x = 4/5 or x = -1
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Cheers,
Stan H.
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