SOLUTION: I am working on a Radical equation not sure how to start other than plug in the numbers for what I am trying to find the right way to start this problem P=1500radicalt+P0 with t= t

Question 293240: I am working on a Radical equation not sure how to start other than plug in the numbers for what I am trying to find the right way to start this problem P=1500radicalt+P0 with t= the year and P0 = population of the town, trying to find out different population scenarios. Thank you
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
P=1500radicalt+P0 with t= the year and P0 = population of the town
--------------
Population = 1500*sqrt(t) + P(0)
---
The graph would be a line with slope = 1500
and y-intercept of P(0).
chart from the year 2010 till 2016; would that mean dividing 1500 into the year sqrt(t) for each year?
----
If P(0) is the population count in 2010,
P(2010) = 1500*sqrt(0) + P(0)
P(2016) = 1500*sqrt(6) + P(0)
=================================
Cheers,
Stan H.
===============================

RELATED QUESTIONS
I am trying to graph a function and I understand how to solve it. What I do not... (answered by stanbon)

I am trying to find slopes of a line when an equation is in the standard form. I am not... (answered by jim_thompson5910)

Write an equation of the line containing the given point and parallel to the given line.... (answered by stanbon)

I am currently working on evaluation exponential function I know how to plug in the... (answered by richwmiller)

Hello, we are working on complex numbers, and I am stuck on this problem. I'm not sure... (answered by Alan3354)

I am working on this problem. I am trying to set it up correctly. The difference of two (answered by jim_thompson5910)

I am working on this problem. I am trying to set it up correctly. The difference of two (answered by scott8148)

Good Morning... This is kind of a new concept for me so I am trying to get some help... (answered by stanbon,mananth)

I am not getting this at all. Here is the equation. One number is six more than another. (answered by mananth)