SOLUTION: Rationalize the denominator. Assume that all variables represent positive real numbers and that the denominator is not zero.
7
____
9- (3 under a radical)
So it's 7 divi
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Question 292392: Rationalize the denominator. Assume that all variables represent positive real numbers and that the denominator is not zero.
7
____
9- (3 under a radical)
So it's 7 divided by 9 minus the square root of 3.
I think. I'm trying to write this so it makes sense.
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Here's how to write it so it makes sense:
7/(9-sqrt(3))
Anyone can read that to mean
First review my lesson on Rationalizing Denominators: http://www.algebra.com/algebra/homework/Radicals/rationalizingdenominators1.lesson
Then you need the conjugate of the denominator. If you have a binomial expression, such as 
, then its conjugate is 
So the conjugate of your denominator is 
Now multiply your expression by 1 in the form of the conjugate divided by itself.
\left(\frac{9\ +\ \sqrt{3}}{9\ +\ \sqrt{3}}\right))
Remember that the product of a binomial and its conjugate is the difference of two squares:
}{81-3}\ =\ \frac{63\ +\ 7\sqrt{3}}{78})
Yes, it's ugly, but at least there is no radical in the denominator.
John
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