SOLUTION: square root 2x-5 = 1+ square root x-3 I understand I have to square both sides. Where I lose it is here: squaring 1 + square root x-3. My textbook has: 2times square root x-3 (en

Question 29115: square root 2x-5 = 1+ square root x-3
I understand I have to square both sides. Where I lose it is here:
squaring 1 + square root x-3. My textbook has: 2times square root x-3 (end square root) + (x-3)
Thanks
Answer by longjonsilver(2297) (Show Source): You can put this solution on YOUR website!

OK, to remove at least some of the square roots here, you could square both sides, as:

This is just like - don't be freaked by the fact we have 2 terms of the right.

Again, square both sides:

(x-7)(x-3) = 0

so x-7=0 OR x-3=0
so x=7 or x=3

This looks rather long, but i have written out every step on a different line so you can see everything.

jon.

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