SOLUTION: how do you solve these equations step by step?
the cubed root of 625 over the cubed root of 25?
the square root of 3 minus 2 times the fourth root of 3 plus 4 times the squared r
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Question 271389: how do you solve these equations step by step?
the cubed root of 625 over the cubed root of 25?
the square root of 3 minus 2 times the fourth root of 3 plus 4 times the squared root of 3 plus 5 times the fourth root of 3?
Answer by jsmallt9(3758) (Show Source): You can put this solution on YOUR website!
First of all, these are expressions not equations. You solve equations. You simplify expressions.
The simplest way to simplify this is to recognize that 625 can be divided evenly by 25. So we can use the property of radicals, , to get 625 and 25 into the same fraction:
Since 625/25 = 25 we get:
The only other simplifying to try is to find perfect cube factors of 25. But there are none (except 1 which is pointless to factor out). So this is our simplified expression.
The first and third terms are like terms. And the second and fourth terms are like terms so we can add and subtract them. Just like x + 4x = 5x, . And just like -2x + 5x = 3x, . So we end up with:
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