SOLUTION: 6x^3+54x^2+120x=0
using x=y^2
Algebra.Com
Question 263572: 6x^3+54x^2+120x=0
using x=y^2
Answer by drk(1908) (Show Source): You can put this solution on YOUR website!
Here is the original problem
step 1 - factor out 6x to get
step 2 - factor the trinomial to get
step 3 - set each part = 0 and solve to get
x = 0
x = -4
x = -5
---
not sure why you would use x=y^2 to solve this question.
RELATED QUESTIONS
x^3 - 3x^2 - 54x =... (answered by scott8148)
6x^(x)-54x=0 (answered by Alan3354)
solve the equation in thev real number system... (answered by ewatrrr)
Find all the zeros of... (answered by Alan3354)
Factor 6x^3+48x^2-54x... (answered by MathLover1)
{{{4x^3-54x^2+180x-125=0}}}
(answered by mangopeeler07)
What is 54x^4-54x^3+30x^2 divided by... (answered by ewatrrr)
Solve... (answered by rwm)
-3x^3+54x=21x^2
(answered by mananth)